Find and Replace text in the entire table using a MySQL query

Usually I use manual find to replace text in a MySQL database using phpmyadmin. I'm tired of it now, how can I run a query to find and replace a text with new text in the entire table in phpmyadmin?

Example: find keyword domain.com, replace with www.domain.com.

 Answers

For a single table update

 UPDATE `table_name`
 SET `field_name` = replace(same_field_name, 'unwanted_text', 'wanted_text')

From multiple tables-

If you want to edit from all tables, best way is to take the dump and then find/replace and upload it back.

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The easiest way I have found is to dump the database to a text file, run a sed command to do the replace, and reload the database back into MySQL.

All commands are bash on Linux, from memory.

Dump database to text file

mysqldump -u user -p databasename > ./db.sql

Run sed command to find/replace target string

sed -i 's/oldString/newString/g' ./db.sql

Reload the database into MySQL

mysql -u user -p databasename < ./db.sql

Easy peasy.

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 UPDATE table SET field = replace(field, text_needs_to_be_replaced, text_required);

Like for example, if I want to replace all occurrences of John by Mark I will use below,

UPDATE student SET student_name = replace(student_name, 'John', 'Mark');

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I believe "swapnesh" answer to be the best ! Unfortunately I couldn't execute it in phpMyAdmin (4.5.0.2) who although illogical (and tried several things) it kept saying that a new statement was found and that no delimiter was found…

Thus I came with the following solution that might be usefull if you exeprience the same issue and have no other access to the database than PMA…

UPDATE `wp_posts` AS `toUpdate`,
(SELECT `ID`,REPLACE(`guid`,'http://old.tld','http://new.tld') AS `guid` 
 FROM `wp_posts` WHERE `guid` LIKE 'http://old.tld%') AS `updated`
SET `toUpdate`.`guid`=`updated`.`guid`
WHERE `toUpdate`.`ID`=`updated`.`ID`;

To test the expected result you may want to use :

SELECT `toUpdate`.`guid` AS `old guid`,`updated`.`guid` AS `new guid`
FROM `wp_posts` AS `toUpdate`,
(SELECT `ID`,REPLACE(`guid`,'http://old.tld','http://new.tld') AS `guid`
 FROM `wp_posts` WHERE `guid` LIKE 'http://old.tld%') AS `updated`
WHERE `toUpdate`.`ID`=`updated`.`ID`;