Why the PHP class does not return < h1 & gt; 404 & lt; / h1 & gt; & lt; p & gt; Not found & lt; / p & gt; `?

Why PHP class does not return <h1>404</h1><p>Not found</p>?

class checkid{
    public $title;
    public $content;
    function status(){
        $this->title='404';
        $this->content='Not found';
    }
}
$checkid=new checkid($url);
//$id=0;
((isset($id)) ? '' : $checkid->status().$title=$checkid->title.$content=$checkid->content);
//Why it does not return `<h1>404</h1><p>Not found</p>`?
echo "<h1>$title</h1><p>$content</p>";

Update: I know well to do it trough

if(isset($id)){}else{
    $checkid->status();
    $title=$checkid->title;
    $content=$checkid->content);
}

but I was worndering if it is possible to make it trough using

((isset($id)) ? '' : $checkid->status().$title=$checkid->title/*here $content break it down*//*.$content=$checkid->content*/);

---

1. Change isset('id') to isset($id).
2. The reason why you were getting <h1>404Not found</h1><p>Not found</p> was because you were concatenating the value of $content to the value of $title.

Also, you're code is quite a mess. I took the liberty of cleaning it up a bit:

class checkid
{
    public $title;
    public $content;
    function status()
    {
        $this->title='404';
        $this->content='Not found';
    }
}
$checkid=new checkid($url);
//$id=0;
if(!isset($id))
{
    $checkid->status();
    $title=$checkid->title;
    $content=$checkid->content;
}
echo "<h1>$title</h1><p>$content</p>";