SELECT x1.id,SUM(x1.amount) as fake_total,COUNT(x1.id) as count, (SELECT SUM(amount) FROM t1 WHERE t1.id=x1.id) as actual_total FROM t1 x1 LEFT JOIN t2 x2 on x2.t1=x1.id GROUP BY x1.id ORDER BY x1.id asc
If you on "EXPLAIN" mode then you will get the below data:
EXPLAIN SELECT x1.id,SUM(x1.amount) as fake_total,COUNT(x1.id) as count, (SELECT SUM(amount) FROM t1 WHERE t1.id=x1.id) as actual_total FROM t1 x1 LEFT JOIN t2 x2 on x2.t1=x1.id GROUP BY x1.id ORDER BY x1.id asc
Actually it will not take too much time to execute
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