MySQL DROP all tables, ignoring foreign keys

Is there a nice easy way to drop all tables from a MySQL database, ignoring any foreign key constraints that may be in there?

 Answers

I found the generated set of drop statements useful, and recommend these tweaks:

1. Limit the generated drops to your database like this:

SELECT concat('DROP TABLE IF EXISTS `', table_name, '`;')
FROM information_schema.tables
WHERE table_schema = 'MyDatabaseName';

Note: This does not execute the DROP statements, it just gives you a list of them. You will need to cut and paste the output into your SQL engine to execute them.

2. Note, per http://dev.mysql.com/doc/refman/5.5/en/drop-table.html, dropping with cascade is pointless / misleading:

"RESTRICT and CASCADE are permitted to make porting easier. In MySQL 5.5, they do nothing."

Therefore, in order for the drop statements to work if you need:

SET FOREIGN_KEY_CHECKS = 0

This will disable referential integrity checks - so when you are done performing the drops you need, you will want to reset key checking with

SET FOREIGN_KEY_CHECKS = 1

3. The final execution should look like:

SET FOREIGN_KEY_CHECKS = 0;
-- Your semicolon separated list of DROP statements here
SET FOREIGN_KEY_CHECKS = 1;

NB: to use output of SELECT easier, mysql -B option can help.

---

Here is SurlyDre's stored procedure modified so that foreign keys are ignored:

DROP PROCEDURE IF EXISTS `drop_all_tables`;

DELIMITER $$
CREATE PROCEDURE `drop_all_tables`()
BEGIN
    DECLARE _done INT DEFAULT FALSE;
    DECLARE _tableName VARCHAR(255);
    DECLARE _cursor CURSOR FOR
        SELECT table_name 
        FROM information_schema.TABLES
        WHERE table_schema = SCHEMA();
    DECLARE CONTINUE HANDLER FOR NOT FOUND SET _done = TRUE;

    SET FOREIGN_KEY_CHECKS = 0;

    OPEN _cursor;

    REPEAT FETCH _cursor INTO _tableName;

    IF NOT _done THEN
        SET @stmt_sql = CONCAT('DROP TABLE ', _tableName);
        PREPARE stmt1 FROM @stmt_sql;
        EXECUTE stmt1;
        DEALLOCATE PREPARE stmt1;
    END IF;

    UNTIL _done END REPEAT;

    CLOSE _cursor;
    SET FOREIGN_KEY_CHECKS = 1;
END$$

DELIMITER ;

call drop_all_tables(); 

DROP PROCEDURE IF EXISTS `drop_all_tables`;

---

Here's a cursor based solution. Kinda lengthy but works as a single SQL batch:

DROP PROCEDURE IF EXISTS `drop_all_tables`;

DELIMITER $$
CREATE PROCEDURE `drop_all_tables`()
BEGIN
    DECLARE _done INT DEFAULT FALSE;
    DECLARE _tableName VARCHAR(255);
    DECLARE _cursor CURSOR FOR
        SELECT table_name 
        FROM information_schema.TABLES
        WHERE table_schema = SCHEMA();
    DECLARE CONTINUE HANDLER FOR NOT FOUND SET _done = TRUE;

    OPEN _cursor;

    REPEAT FETCH _cursor INTO _tableName;

    IF NOT _done THEN
        SET @stmt_sql = CONCAT('DROP TABLE ', _tableName);
        PREPARE stmt1 FROM @stmt_sql;
        EXECUTE stmt1;
        DEALLOCATE PREPARE stmt1;
    END IF;

    UNTIL _done END REPEAT;

    CLOSE _cursor;

END$$

DELIMITER ;

call drop_all_tables(); 

DROP PROCEDURE IF EXISTS `drop_all_tables`;

---

You can do:

select concat('drop table if exists ', table_name, ' cascade;')
  from information_schema.tables;

Then run the generated queries. They will drop every single table on the current database.

Here is some help on drop table command.

---

Here is an automated way to do this via a bash script:

host=$1
dbName=$2
user=$3
password=$4

if [ -z "$1" ]
then
    host="localhost"
fi

# drop all the tables in the database
for i in `mysql -u$user -p$password $dbName -e "show tables" | grep -v Tables_in` ; do  echo $i && mysql -u$user -p$password $dbName -e "SET FOREIGN_KEY_CHECKS = 0; drop table $i ; SET FOREIGN_KEY_CHECKS = 1" ; done

---

In php its as easy as:

$pdo = new PDO('mysql:dbname=YOURDB', 'root', 'root');

$pdo->exec('SET FOREIGN_KEY_CHECKS = 0');

$query = "SELECT concat('DROP TABLE IF EXISTS ', table_name, ';')
          FROM information_schema.tables
          WHERE table_schema = 'YOURDB'";

foreach($pdo->query($query) as $row) {
    $pdo->exec($row[0]);
}

$pdo->exec('SET FOREIGN_KEY_CHECKS = 1');

Just remember to change YOURDB to the name of your database, and obviously the user/pass.

---

In a Linux shell like bash/zsh:

DATABASE_TO_EMPTY="your_db_name";
{ echo "SET FOREIGN_KEY_CHECKS = 0;" ; \
  mysql "$DATABASE_TO_EMPTY" --skip-column-names -e \
  "SELECT concat('DROP TABLE IF EXISTS ', table_name, ';') \
   FROM information_schema.tables WHERE table_schema = '$DATABASE_TO_EMPTY';";\
  } | mysql "$DATABASE_TO_EMPTY"

This will generate the commands, then immediately pipe them to a 2nd client instance which will delete the tables.

The clever bit is of course copied from other answers here - I just wanted a copy-and-pasteable one-liner (ish) to actually do the job the OP wanted.

Note of course you'll have to put your credentials in (twice) in these mysql commands, too, unless you have a very low security setup. (or you could alias your mysql command to include your creds.)

---

This is a pretty old post, but none of the answers here really answered the question in my opinion, so I hope my post will help people!

I found this solution on another question that works really well for me:

mysql -Nse 'show tables' DB_NAME | while read table; do mysql -e "SET FOREIGN_KEY_CHECKS=0; truncate table \`$table\`" DB_NAME; done

That will actually empty all your tables in the database DB_NAME, and not only display the TRUNCATE command line.

Hope this helps!

---

This solution is based on @SkyLeach answer but with the support of dropping tables with foreign keys.

echo "SET FOREIGN_KEY_CHECKS = 0;" > ./drop_all_tables.sql
mysqldump --add-drop-table --no-data -u user -p dbname | grep 'DROP TABLE' >> ./drop_all_tables.sql
echo "SET FOREIGN_KEY_CHECKS = 1;" >> ./drop_all_tables.sql
mysql -u user -p dbname < ./drop_all_tables.sql

---

Best solution for me so far

Select Database -> Right Click -> Tasks -> Generate Scripts - will open wizard for generating scripts. After choosing objects in set Scripting option click Advanced Button. Under "Script DROP and CREATE" select Script DROP.

Run script.